5x^2-50x-135=0

Solution for 5x^2-50x-135=0 equation:

5x^2-50x-135=0

a = 5; b = -50; c = -135;
Δ = b2-4ac
Δ = -502-4·5·(-135)
Δ = 5200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5200}=\sqrt{400*13}=\sqrt{400}*\sqrt{13}=20\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-20\sqrt{13}}{2*5}=\frac{50-20\sqrt{13}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+20\sqrt{13}}{2*5}=\frac{50+20\sqrt{13}}{10}
$